Question

Answer 1

Bài 2: 

a) Ta có: \(A=\left(x+2\right)\cdot\sqrt{\dfrac{2x-3}{x+2}}\)

\(=\dfrac{\left(x+2\right)\cdot\sqrt{2x-3}}{\sqrt{x+2}}\)

\(=\sqrt{\left(x+2\right)\left(2x-3\right)}\)

b) Ta có: \(B=\dfrac{\sqrt{x^2-4}}{4-2x}\)

\(=\dfrac{\sqrt{x-2}\cdot\sqrt{x+2}}{-2\left(x-2\right)}\)

\(=\dfrac{-\sqrt{x+2}}{2\cdot\sqrt{x-2}}\)