Question

Answer 1

bạn đăng tách ra cho m.n cùng giúp nhé

Với \(x>0;x\ne4\)

\(A=\dfrac{3}{\sqrt{x}-2}-\dfrac{2\sqrt{x}+3}{x-4}=\dfrac{3\sqrt{x}+6-2\sqrt{x}-3}{x-4}\)

\(=\dfrac{\sqrt{x}-3}{x-4}\)

Ta có : \(P=A.B=\dfrac{\sqrt{x}-3}{x-4}.\dfrac{x-4}{\sqrt{x}}=\dfrac{\sqrt{x}-3}{\sqrt{x}}\)

Ta có : \(P=\dfrac{\sqrt{x}+7}{2}\Rightarrow\dfrac{\sqrt{x}-3}{\sqrt{x}}=\dfrac{\sqrt{x}-7}{2}\)

\(\Rightarrow2\sqrt{x}-6=x-7\sqrt{x}\Leftrightarrow x-9\sqrt{x}+6=0\Leftrightarrow x=\dfrac{9\pm\sqrt{57}}{2}\)