C1: A=(6−\(\dfrac{2}{3}\)+\(\dfrac{1}{2}\))−(5+\(\dfrac{5}{3}\)−\(\dfrac{3}{2}\))−(3−\(\dfrac{7}{3}\)+\(\dfrac{5}{2}\))
A=(\(5\dfrac{1}{3}\)+\(\dfrac{1}{2}\))−(\(6\dfrac{2}{3}\)−\(\dfrac{3}{2}\))−(\(\dfrac{2}{3}\)+\(\dfrac{5}{2}\))
A=\(5\dfrac{5}{6}\)−\(5\dfrac{1}{6}\)−\(3\dfrac{1}{6}\)
A=\(-2\dfrac{1}{2}\)
C2: A=(6−\(\dfrac{2}{3}\)+\(\dfrac{1}{2}\))−(5+\(\dfrac{5}{3}\)−\(\dfrac{3}{2}\))−(3−\(\dfrac{7}{3}\)+\(\dfrac{5}{2}\))
A=6−\(\dfrac{2}{3}\)+\(\dfrac{1}{2}\)−5−\(\dfrac{5}{3}\)+\(\dfrac{3}{2}\)−3+\(\dfrac{7}{3}\)−\(\dfrac{5}{2}\)
A=(6−5−3)−(\(\dfrac{2}{3}\)+\(\dfrac{5}{3}\)−\(\dfrac{7}{3}\))+(\(\dfrac{1}{2}\)+\(\dfrac{3}{2}\)−\(\dfrac{5}{2}\))
A=−2+(−\(\dfrac{1}{2}\))=−2\(\dfrac{1}{2}\)
Ta có: \(A=\left(6-\dfrac{2}{3}+\dfrac{1}{2}\right)-\left(5+\dfrac{5}{3}-\dfrac{3}{2}\right)-\left(3-\dfrac{7}{3}+\dfrac{5}{2}\right)\)
\(=6-\dfrac{2}{3}+\dfrac{1}{2}-5-\dfrac{5}{3}+\dfrac{3}{2}-3+\dfrac{7}{3}-\dfrac{5}{2}\)
\(=-2-\dfrac{1}{2}=\dfrac{-5}{2}\)
