Ta có: \(\widehat{xOt}=\widehat{yOz}\)(hai góc đối đỉnh)
mà \(\widehat{xOt}+\widehat{yOz}=100^0\)
nên \(\widehat{xOt}=\widehat{yOz}=\dfrac{100^0}{2}=50^0\)
Vậy: \(\widehat{xOt}=50^0\); \(\widehat{yOz}=50^0\); \(\widehat{yOt}=130^0\); \(\widehat{xOz}=130^0\)
