HOC24
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Môn học
Chủ đề / Chương
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ghê ghê
nice
2100 > 10249
K3PO4
Ba(OH)2
CrO3
\(\left[\left(x-2\right)^3-11\right]^3=4^6\)
<=> \(\left[\left(x-2\right)^3-11\right]^3-16^3=0\)
<=> \(\left[\left(x-2\right)^3-11-16\right]\left\{\left[\left(x-2\right)^3-11\right]^2+16\left[\left(x-2\right)^3-11\right]+256\right\}=0\)
<=> \(\left[{}\begin{matrix}\left(x-2\right)^3-11-16=0\\\left[\left(x-2\right)^3-11\right]+16\left[\left(x-2\right)^3-11\right]+256=0\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=5\\x=0,4048554057\approx0,4=\dfrac{2}{5}\end{matrix}\right.\)
(2x - 5)5 = 310
<=> (2x - 5)5 = 95
<=> \(\sqrt[5]{\left(2x-5\right)^5}=\sqrt[5]{9^5}\)
<=> 2x - 5 = 9
<=> 2x = 9 + 5
<=> 2x = 14
<=> x = 7
-134 + 10
= -124
???
\(\left(x-\dfrac{1}{2}\right)^2=4\)
<=> \(\left(x-\dfrac{1}{2}\right)^2-2^2=0\)
<=> \(\left(x-\dfrac{1}{2}-2\right)\left(x-\dfrac{1}{2}+2\right)=0\)
<=> \(\left[{}\begin{matrix}x-\dfrac{1}{2}-2=0\\x-\dfrac{1}{2}+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)