`2^24 = 2^(3.8) = (2^3)^8 = 8^8`

`2/3.x = (-1)/8`

`<=> x = (-1)/8  :2/3`

`<=> x = (-1)/8 . 3/2`

`<=> x= (-3)/16`

`b` sai vì `0,5.(0,5)^2 = 0,125 = 1/8` chứ không bằng `1/4`

  `(x-1)^3-3=5`

`<=>(x-1)^3 = 5+3`

`<=>(x-1)^3 = 8`

`<=>(x-1)^3 = 2^3`

`<=> x-1 = 2`

`<=> x = 2+1`

`<=> x = 3`

Vậy `x = 3`

`x+1/2  =3/4`

`<=> x = 3/4 - 1/2`

`<=> x = 6/8 - 4/8`

`<=> x = 1/4`

Vậy `x = 1/4`

`ƯCLN(a,b,c) = ƯCLN( 2^2 . 3^2 . 5 , 2^2  . 3. 7^2 ,2^3 . 3 . 5^2)=2^2 . 3 = 12`

`=>` Chọn `A.12`

Ta có : 

`20 = 2^2.5`

`30 = 5.2.3`

`=> ƯCLN(20,30) = 2.5=10`

---------------------------

Ta có : 

`36 = 2^2 . 3^2`

`18=2 . 3^2`

`=> ƯCLN(36,18) = 3^2.2 = 18`

---------------------------

Ta có :

`12 = 2^2.3`

`16=2^4`

`24= 2^3.3`

`=>ƯCLN(12,16,24)= 2^2=4`

`c)`

`(-2)^400 =2^400 = (2^4)^100 = 16^100`

`(-3)^300 = (3)^300 = (3^3)^100 =  27^100`

Vì `16^100 <27^100`

`=> (-2)^400 < (-3)^300`

`b)`

`4^100 =  (4^2)^50 = 16^50`

`3^150 = (3^3)^50 = 27^50`

Vì `16^50 < 27^50`

`=> 4^100 < 3^150`

`a) `

`(x-15)xx15=0`

`<=> x-15 = 0 : 15`

`<=> x-15 = 0`

`<=> x = 0 + 15`

`<=> x =15`

`b)`

`32.(x-10)=32`

`<=> x - 10 = 32:32`

`<=>x-10=1`

`<=> x = 1+10`

`<=> x =11`

`c)`

`(x-5).(x-7)=0`

`<=>` \(\left[ \begin{array}{l}x-5 = 0\\x-7=0\end{array} \right.\) 

`<=>` \(\left[ \begin{array}{l}x=5\\x=7\end{array} \right.\) 

`d)`

`(x-35)xx35=35`

`<=> x - 35 = 35:35`

`<=> x - 35 = 1`

`<=> x = 1+35`

`<=> x = 36`