Var n,i,so:integer;

Begin

Write('Nhap n = ');readln(n);

Writeln('Cac so chan tu 1 den n la: ');

For i:=1 to n do

If i mod 2 = 0 then write(i,'   ');

Readln;

End.

Var a:array[1..100] of real;

n,i:integer;

Begin

Write('Nhap so luong so n = ');readln(n);

For i:=1 to n do

Begin

Write('Nhap so thu ',i);readln(a[i]);

End;

Writeln('Cac so vua nhap la:');

For i:=1 to n do

Begin

Write(a[i]:10:2,'   ');

Readln;

End.

Var s,n,i,dem,so:integer;

Begin

Write('Nhap so luong so n = ');readln(n);

For i:=1 to n do

Begin

Write('Nhap so thu ',i);readln(so);

If so mod 2 = 0 then

Begin

dem:=dem+1;

s:=s+so;

End;

End;

Writeln('Co ',dem,' so chan');

Write('Tong cac so chan la ',s);

Readln;

End.

Var s,i,n,so:longint;

Begin

Write('nhap so luong so N = ');readln(n);

For i:=1 to n do

Begin

Write('Nhap so thu ',i,' = ');readln(so);

If so mod 5 = 0 then s:=s+so*so;

End;

Write('Tong binh phuong cac boi cua 5 trong day la ',s);

Readln;

End.

Var s,i,n:longint;

Begin

Write('nhap so luong so N = ');readln(n);

For i:=1 to n do

Begin

Write('Nhap so thu ',i,' = ');readln(so);

If so mod 5 = 0 then s:=s+so*so;

End;

Write('Tong binh phuong cac boi cua 5 trong day la ',s);

Readln;

End.

Pin nó chai đó em, từ từ rồi sạc nó không vô luôn

1. A

2. C

3. C

4. B

5. C

6. C

7. A

8. B

9. D

10. C

11. A

12. D

13. C

14. A

\(\dfrac{5}{6}=\dfrac{10}{12}=\dfrac{15}{18}=\dfrac{20}{24}=\dfrac{25}{30}=\dfrac{30}{36}\)

\(\dfrac{7}{12}=\dfrac{14}{24}=\dfrac{21}{36}=\dfrac{28}{48}=\dfrac{35}{60}=\dfrac{42}{72}\)

\(\dfrac{8}{15}=\dfrac{16}{30}=\dfrac{24}{45}=\dfrac{32}{60}=\dfrac{40}{75}=\dfrac{48}{90}\)

\(\dfrac{17}{24}=\dfrac{34}{48}=\dfrac{51}{72}=\dfrac{68}{96}=\dfrac{85}{120}=\dfrac{102}{144}\)

\(\left|2x+3\right|\ge18\)

\(\Leftrightarrow2x+3>18;2x+3< -18\)

*) \(2x+3>18\)

\(\Leftrightarrow2x>15\)

\(\Leftrightarrow x>\dfrac{15}{2}\)

*) \(2x+3< -18\)

\(\Leftrightarrow2x< -21\)

\(\Leftrightarrow x< -\dfrac{21}{2}\)

Vậy \(x>\dfrac{15}{2}\); \(x< -\dfrac{21}{2}\)

\(5x-2\left(x-1\right)=-4.8\)

\(5x-2x+2=-32\)

\(3x=-32-2\)

\(3x=-34\)

\(x=-\dfrac{34}{3}\)