HOC24
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Môn học
Chủ đề / Chương
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1d2b3b4b
(2x+2).(2x+2)-(3x-1).(3x+1)=(2x+2)2- 9x2-1=4x2+8x+4-9x2-1=-5x2+8x+3
d) 99^20 và 9999^10\(99^{20}=\left(99^2\right)^{10}\)=\(9801^{10}\)=>99^20 <9999^10
c) 5^36 và 11^24\(5^{36}=\left(5^6\right)^6=15625^6\)\(11^{24}=\left(11^4\right)^6=14614^6\)=> 5^36 > 11^24
b) 202^303 và 303^202\(202^{303}=\left(202^3\right)^{100}=8242408^{100}\)\(302^{202}=\left(302^2\right)^{100}=91204^{100}\)\(8242408^{100}>91204^{100} \)202^303 > 303^202
a)\(7^{30}=\left(7^3\right)^{10}=343^{10}\)\(3^{40}=\left(3^4\right)^{10}=81^{10}\)mà \(343^{10}>81^{10}\)=>\(7^{30}>3^{40}\)
\(\left(a\right)\)\(x-\dfrac{1}{4}=\dfrac{-1}{6}\)\(x=\dfrac{1}{12}\)/\(x+\dfrac{1}{3}\)/=3=> \(x+\dfrac{1}{3}=3\) hoặc \(-x-\dfrac{1}{3}=3\)=> x=\(\dfrac{8}{3}\) hoặc x= \(\dfrac{-10}{3}\)
a. 45.34 + 45.37 + 71.23 + 33.71=45.(34+37)+71(23+33)= 45.71+71.56=71(45+56)=71.101=7171b. 23.46 + 23.52 + 98.35 + 98.42= 23.(46 + 52 )+ 98.(35 + 42)= 23.98+ 98.77= 98.(23+77)=98 . 100=9800c. 27.34 + 27.56 + 90.20 + 26.90= 27.(34 +56) + 90.(20 + 26)= 27.90+ 90.46=90.(27+46)=90.73=6570d. 12.37 + 12.78 + 115.29 + 115.59=12.(37 + 78) + 115.(29 + 59)=12.115+115.88=115(12+88)=115.100=11500
bài 21)/2x-7/+\(\dfrac{1}{2}=1\dfrac{1}{2}\)/2x-7/+\(\dfrac{1}{2}=\dfrac{3}{2}\)/2x-7/=1=> 2x-7=1 hoặc -2x+7 =1 2x=8 hoặc -2x=-6 x=4 hoặc x=3