HOC24
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Thiếu kiểu hình nhé bạn!
\(b.\left(2x-1\right)^2-25=0\)
<=>\(\left(2x-1-5\right)\left(2x-1+5\right)=0\)
<=>\(\left[{}\begin{matrix}2x=6\\2x=-4\end{matrix}\right.< =>\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
\(a.2x^2-16x=0< =>2x\left(x-8\right)=0\)
\(< =>\left[{}\begin{matrix}2x=0\\x-8=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=0\\x=8\end{matrix}\right.\)
Look! He (leave) __is leaving_______ the house.
Quiet please! I (write) _am writing _____ a test.
She usually (walk)___walks___ to school.
But look! Today she (go) __is going___ by bike.
Every Sunday we (go) ___go____ to see my grandparents.
He often (go)__goes______ to the cinema.
We (play) _____are playing _ Monopoly at the moment.
The child seldom (cry)___cries _______ .
I (not / do) am not doing____ anything at the moment.
(watch / he)___Does he watch _____ the news regularly?
\(a)=x^3(x+3)+x(x+3)=(x^2+x)(x+3)=x(x+1)(x+3)\\b)=(x+3y)^2-4z^2=(x+3y-2z)(x+3y+2z)\\c)=2x^2-2x-7x+7=2x(x-1)-7(x-1)=(2x-7)(x-1)\)
P: AaBb x aaBb
Gp AB,Ab,aB,ab. aB,ab
F1: 1AABB:2AABb:2Aabb:1AaBB:1AAbb:1aabb:1aaBb
Kiểu gen:3A_B_:3A_bb:1aaB_:1aabb
=AC+AD+BC+BD
Kiểu gen: Thân cao: AA. Thân thấp: aa
P(t/c). AA( thân cao). x. aa( thân thấp)
Gp. A. a
F1: Aa(100% thân cao)
F1xF1: Aa( thân cao). x. Aa( thân cao)
GF1: A,a. A,a
F2: 1AA:2Aa:1aa
kiểu hình:3 thân cao:1 thân thấp