\(B=\dfrac{\sqrt{24x^3}}{\sqrt{6x}}\)

\(=\sqrt{\dfrac{24x^3}{6x}}\)

\(=\sqrt{4x^2}=2x\)

A là "whose" nghĩa là "của ai" nên không chọn.

Từ trái qua phải nhé.

\(\begin{matrix}x=0;2\\y=-\dfrac{3}{2};\dfrac{3}{4};3\end{matrix}\)

\(320-20.\left[\left(3^3+20^0\right):7-1\right]\)

\(=320-20.\left[\left(27+1\right):7-1\right]\)

\(=320-20.\left(28:7-1\right)\)

\(=320-20.\left(4-1\right)\)

\(=320-20.3\)

\(=320-60\)

\(=260\)

1. Linda drinks three bottles of water everyday.

2. The stadium is behind our school.

3. Why you mustn't eat too much chocolate?

4. Look! What are these children doing?

5. How do you eat many oranges every day?

6. Chocolate has a lot of sugar and fat.

7. Are there any bookshops near here?

8. There are some apples in the fridge.

1. D

2. B

a/ Tất cả \(x\in Z;x\ge0\)

b/ Không có số nguyên x nào thỏa mãn điều kiện.

c/ Tất cả \(x\in Z;x\le0\)

d/ Không có số nguyên x nào thỏa mãn điều kiện.

as

1. C

2. C

3. A

4. D

5. C

Ta có: \(AB+CD=MN.2=10.2=20\left(cm\right)\)

\(\dfrac{AB}{CD}=\dfrac{2}{3}\Rightarrow\dfrac{AB}{2}=\dfrac{CD}{3}\)

Áp dụng t/c của dãy tỉ số bằng nhau:

\(\dfrac{AB}{2}=\dfrac{CD}{3}=\dfrac{AB+CD}{2+3}=\dfrac{20}{5}=4\)

\(\Rightarrow\left\{{}\begin{matrix}AB=4.2=8\left(cm\right)\\CD=4.3=12\left(cm\right)\end{matrix}\right.\)