1)  MgO+HCl→MgCl₂+H₂O

2)nMgO=8/40=0.2 mol

MgO+2HCl→MgCl₂+H₂O

0.2                 0.2                mol

mMgCl₂=0.2*95=19 g

3)nHCl=0.2*2=0.4 mol

mHCl=0.4 * 36.5=14.6 g

4)mdd HCl=14.6*100/10=146 g

mdd muối sau pứ=8+146=154 g

C%=19/154 *100%=12.33 %

nHCl =4*0.25=1 mol

Al₂O₃+6HCl→2AlCl₃+3H₂O

   1                      2                     mol

C_M=2/0.25=8 M

CaO,FeO,SO₂,NO₂

mKOH=80*28%=22.4 g

mCUSO₄=171.6*18.65%=32 g

m_D=22.4+32=54.4 g

mdd_D=80+171.6=251.6 g

C%=mct/mdd *100%

      =54.4/251.6 *100%=21.621%

Đoạn mạch nối tiếp hay song song v bn =))

1,2MB=1200000B

Số trang sách:1200000:300=4000 (trang)

n_C=3.1/12=0.258 mol

        C   +  O₂  →  CO₂

      0.258  0.258             mol

V_O2=0.258*22.4=5.7792 l

mCO2=3.1+0.258*32=11.356 g