x + \(\dfrac{1}{3}\)=\(\dfrac{7}{26}.\dfrac{-13}{6}\)

\(\dfrac{3}{5}+\dfrac{-7}{4}+\dfrac{1}{2}\)

\(\left[{}\begin{matrix}\\\end{matrix}\right.\dfrac{-5}{12}+\dfrac{6}{11}\) ] +[ \(\dfrac{7}{18}+\dfrac{5}{11}+\dfrac{5}{12}\)]

\(\dfrac{-8}{3}+\dfrac{-1}{3}< x< \dfrac{-2}{7}+\dfrac{-5}{7}\)