a, 3.(2-2x)=4.(x-1)

6 - 6x = 4x -4

4x + 6x = 6 + 4

10x = 10

x=1

155 bo

\(\left(\sqrt{2x-1}+1\right)^2-1=0\)

\(\left(\sqrt{2x-1}+1\right)^2=1\)

Th1: \(\sqrt{2x-1}+1=-1\)

\(\sqrt{2x-1}=-2\)

\(\Rightarrow x\in\varphi\)

Th2:\(\sqrt{2x-1}+1=1\)

\(\sqrt{2x-1}=0\)

\(\Rightarrow2x-1=0\)

\(2x=1\)

\(x=\frac{1}{2}\)

Vậy \(x=\frac{1}{2}\)