4 : 3 = 2 vì tứ chia tam xẽ = 3

\(pt\Rightarrow\frac{4}{x^2-3x+2}=\frac{1}{x^2-4x+3}\)           ĐKXĐ: \(\hept{\begin{cases}x\ne1\\x\ne2\\x\ne3\end{cases}}\)

\(\Rightarrow\frac{4}{\left(x-1\right)\left(x-2\right)}=\frac{1}{\left(x-1\right)\left(x-3\right)}\)

\(\Rightarrow4\left(x-3\right)=x-2\)

\(\Rightarrow4x-12=x-2\)

\(\Rightarrow3x=10\)

\(\Rightarrow x=\frac{10}{3}\)

                                                           Vậy x = 10/3