\(\frac{423134.846267-423133}{423133.846267+423134}=\frac{423133.846267+846247-423133}{423133.846267+423134}\)

                                                    \(=\frac{423133.846267+423134}{423133.846267+423134}=1\)

x + 5 + 3 = 10

x + 8 = 10

x = 10 - 8

x = 2 

x + 1 + 9 = 20

x + 10 = 20

x = 20 - 10

x = 10 

Đặt tên biểu thức là A

 \(A=\)\(1+3+3^2+3^3+...+3^{100}\)

\(\Rightarrow\)\(3A=3.\left(1+3+3^2+3^3+...+3^{100}\right)\)

\(3A=3+3^2+3^3+3^4+...+3^{101}\)

\(\Rightarrow3A-A=\left(3+3^2+3^3+3^4+...+3^{101}\right)-\left(1+3+3^2+3^3+...+3^{100}\right)\)

\(2A=3^{101}-1\)

\(\Rightarrow A=\left(3^{101}-1\right):2\)
 

\(\left(2x-1\right)^6=\left(2x-1\right)^8\)

\(\left(2x-1\right)^2=1\)

Th1: 2x - 1 = 1

2x =2

x=1

Th2: 2x -1 = -1

2x = 0

x=0

Vậy............................

-15 k mmik nya meo meo

A=1+3+3^2+....+3^100
\Rightarrow 3A=3+3232+3333+...+31013101
\Rightarrow3A-A=2A=(3+3232+3333+31013101)-(1+3+3232+....+31003100)
=31013101-1
\RightarrowA=(31013101-1):2 

Còn cáchtinshh máy tính nữa 

 Gọi tổng cần tính là S 
3S = 3^2 + 3^3 + 3^4 + ... + 3^101 (1) 
S = 3 + 3^2 + 3^3 + ... + 3^100 (2) 
(1) trừ (2) ---> 2S = 3^101 - 3 = 3(3^100 - 1) 
---> S = 3(3^100 - 1)/2

HỌC TỐT NHÉ

em chiu

(2x - 1)⁶ = (2x - 1)⁸

(2x - 1)⁶ = (2x - 1)⁶ . (2x - 1)²

=> (2x - 1)² = 1

=> \(\hept{\begin{cases}2x-1=1\\2x-1=-1\end{cases}\Rightarrow\hept{\begin{cases}x=1\\x=0\end{cases}}}\)

ta suy ra UCLN (96,36)=12

vay chia nhieu nhat la 12 dia

so keo moi dia co: 96:12=8 keo

so banh moi dia co: 36 :12= 3 banh