\(a,\sqrt{3}và1,7\left(3\right)=1,73205...và1,7\left(3\right)\\ \Rightarrow1,73205>1,7\left(3\right)\\ \Rightarrow\sqrt{3}>1,7\left(3\right).\\ b,-2,236và-\sqrt{5}=-2,236và-2,23606...\\ \Rightarrow-2,236>-2,23606\\ \Rightarrow-2,236>-\sqrt{5} \)

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\(a,A=\left[6.\left(-\dfrac{1}{3}\right)^2-3.\left(-\dfrac{1}{3}\right)+1\right]:\left(-\dfrac{1}{3}-1\right)^2\\ \Rightarrow A=\left[6.\left(-\dfrac{1}{3}\right).\left(-\dfrac{1}{3}\right)-3.\left(-\dfrac{1}{3}\right)\right]:\left(-\dfrac{1}{3}-1\right)^2\\ \Rightarrow A=\left[-2.\left(-\dfrac{1}{3}\right)-3.\left(-\dfrac{1}{3}\right)\right]:\left(-\dfrac{4}{3}\right)^2\\ \Rightarrow A=\left[\left(-\dfrac{1}{3}\right).\left(-2-3\right)\right]:\dfrac{16}{9}\\ \Rightarrow A=\left[\left(-\dfrac{1}{3}\right).\left(-5\right)\right]:\dfrac{16}{9}\\ \Rightarrow A=\dfrac{5}{3}.\dfrac{9}{16}\\ \Rightarrow A=\dfrac{45}{48}.\)