Bài 2

b, \(10^x\) : \(5^y\) = \(20^y\)

tìm x nguyên biết

a, \(^{5^x}\)+\(^{5^{x+2}}\)=650

b,\(^{3^{x-1}}\)+5.\(^{3^{x-1}}\)=162

b. 1-3+\(^{3^2}\)-\(^{3^3}\)+.....+\(\left(-3\right)^x\)=\(\frac{9^{1006}-1}{4}\)

\(\frac{x-1}{2001}\)+\(\frac{x-2}{2010}\)-\(\frac{x-3}{2009}\)=\(\frac{x-4}{2008}\)