\(n_S=\dfrac{3,2}{32}=0,1\left(mol\right)\)
PTHH: \(S+O_2-t^o->SO_2\)
a. Theo PT ta có: \(n_{O_2}=n_S=0,1\left(mol\right)\)
=> \(V_{O_2}=0,1.22,4=2,24\left(l\right)\)
=> \(V_{kk}=5.n_{O_2}=5.2,24=11,2\left(l\right)\)
b. Theo PT ta có: \(n_{SO_2}=n_S=0,1\left(mol\right)\)
=> \(V_{SO_2\left(đktc\right)}=0,1.22,4=2,24\left(l\right)\)

1m=10 dm tích mk nha

ong tho