Tìm GTLN của A

A=\(\frac{\sqrt{a}+1}{\sqrt{a}-3}\)

Tìm GTLN của A

A=\(\frac{\sqrt{x}}{x+\sqrt{x}+1}\)

\(\left(\frac{x-5\sqrt{x}}{x-25}-1\right):\left(\frac{25-x}{x+2\sqrt{x}-15}-\frac{\sqrt{x}+3}{\sqrt{x}+5}+\frac{\sqrt{x}-5}{\sqrt{x}-3}\right)\)

\(\frac{15\sqrt{x}-11}{x+2\sqrt{x}-3}+\frac{\sqrt{x}+1}{1-\sqrt{x}}+\frac{2\sqrt{x}+3}{\sqrt{x}+3}\)

\(\frac{x\sqrt{x}+26\sqrt{x}-19}{x+2\sqrt{x}-3}-\frac{2\sqrt{x}}{\sqrt{x}-1}+\frac{\sqrt{x}-3}{\sqrt{x}+3}\)

\(\frac{\sqrt{3-\sqrt{5}\left(3+\sqrt{5}\right)}}{\sqrt{10}+\sqrt{2}}\)

\(\frac{2\sqrt{8}-\sqrt{12}}{\sqrt{18}-\sqrt{48}}-\frac{\sqrt{5}+\sqrt{27}}{\sqrt{30}+\sqrt{162}}\)

\(\frac{10+2\sqrt{10}}{\sqrt{2}+\sqrt{5}}+\frac{8}{1-\sqrt{5}}\)

\(\sqrt{2-\sqrt{3}}\left(\sqrt{6}+\sqrt{2}\right)\)

\(\left(\sqrt{6}+\sqrt{2}\right)\left(\sqrt{3}-2\right)\sqrt{\sqrt{3}+2}\)