Tìm x;y;z:

\(\dfrac{6}{11}\)x=\(\dfrac{9}{2}\)y=\(\dfrac{18}{5}\)z và -x+y+z= -120

Tính:

B=[-\(\sqrt{2,25}\)+4\(\sqrt{\left(-2,15\right)^2}\)-(3\(\sqrt{\dfrac{7}{6}}\))^2].\(\sqrt{1\dfrac{9}{16}}\)

C=\(3\dfrac{1}{2}\).\(\dfrac{4}{49}\)-[2,(4).\(2\dfrac{5}{11}\)]:(\(\dfrac{-42}{5}\))