mình tick cho bạn ấy mà bạn ấy ko tick cho mình , lưu ý mình ko phải là huy, bạn ấy còn bảo mình hâm hấp

\(4^{^{ }x+1}=8^2\)

\(\Rightarrow2^{2\left(x+1\right)}=2^6\)

\(\Rightarrow2\left(x+1\right)=6\)

\(\Rightarrow x+1=6\div2=3\)

\(\Rightarrow x=3-1=2\)

vậy x=2

\(\left(\dfrac{2016}{2017}-\dfrac{3}{2015}\right)\div\left(\dfrac{-2}{3}\right)-\left(\dfrac{2012}{2015}-\dfrac{1}{2017}\right)\div\left(\dfrac{-2}{3}\right)\)

\(=\left[\left(\dfrac{2016}{2017}-\dfrac{3}{2015}\right)-\left(\dfrac{2012}{2015}-\dfrac{1}{2017}\right)\right]\div\left(\dfrac{-2}{3}\right)\)

\(=\left(\dfrac{2016}{2017}-\dfrac{3}{2015}-\dfrac{2012}{2015}+\dfrac{1}{2017}\right)\div\left(\dfrac{-2}{3}\right)\)

\(=\left[\left(\dfrac{2016}{2017}+\dfrac{1}{2017}\right)+\left(-\dfrac{3}{2015}-\dfrac{2012}{2015}\right)\right]\div\left(\dfrac{-2}{3}\right)\)

\(=\left[1+\left(-1\right)\right]\div\left(\dfrac{-2}{3}\right)\)

\(=0\div\left(\dfrac{-2}{3}\right)=0\)

mình có gì sai sót xin bạn thông cảm cho