HOC24
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Ta có:
\(\frac{2n+1}{n-1}=\frac{2n-2+3}{n-1}=\frac{2\left(n-1\right)+3}{n-1}=2+\frac{3}{n-1}\)
Để (2n+1) chia hết cho (n-1) thì \(\frac{3}{n-1}\)phải có GTN
\(\Rightarrow\)3 chia hết cho n-1
\(\Rightarrow n-1\inƯ\left(3\right)\Rightarrow n-1\in\left\{1;3\right\}\Rightarrow n\in\left\{2;4\right\}\)
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tuổi ông hơn cháu
kiển tố là tổ kiến
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