Viết phương trình Cla-pê-rôn – Men-đê-lê-ép và nêu rõ các đại lượng có trong phương trình.

Trong tgian bạn Hùng đi thì bạn lên đi đc là;

(5:2)x6.1\(=\)

a)

A : Could you tell ..me.. how ..to go.... to the bookstore

B: Go ...straight..... ahead. Take the first street ...on your right..

The bookstore in on your....right.....

b)

C : Could you show me ....the way to...... the bank, please ?

D: Go ...straight ahead........ Take the ...second.... street on .the left ......

c)

E : ........Could you......... tell ...me the way to.............the bakery ?

F : ..........Go straigh ahead. Take the third street on your left ..............................................

...............It on your left ...............................

d)

G : ..Could you..........show......me the way to........the fashion shop, please ?

H : .............Go straight ahead, ...take the second street on the left .....................................................

....................it opposite the hotel.......................

e )

I : ..Could you............tell ......me the way to...............................hospital, please ?

J : .....go ..........................................

..................................................................

f ) ( bus stop )

.....could you show me the way to the bus stop..............?

.........turn left , .....

.......it next to the museum ..................................................

g ) (toy store )

........could...you...tell...me ...way...to...the..toy.store.......?

..............go...straight...ahead, take...the...second...street..................................................

....................................it is opposite...the...school....................................

h ) ( restaurant )

.......could...you...show...me...the...way...to..the...restaurant.................................................?

................go...straight...ahead,...take..the...first..street..............................................

.....................it...next...to...the...supermarket...........................................

a, |x+1| +2x \(=\)-2

\(\Leftrightarrow\) |x+1|\(=\)-2-2x (*)

TH1: Nếu x+1\(\ge0\)\(\Leftrightarrow x\ge-1\)thì \(\left|x+1\right|=x+1\)

Thay vào (*) ta có:

\(x+1=-2-2x\)

\(\Leftrightarrow x+2x=-2-1\)

\(\Leftrightarrow3x=-3\)

\(\Leftrightarrow x=-1\)(TMĐK)

TH2: Nếu \(x+1< 0\Leftrightarrow x< -1\Rightarrow\left|x+1\right|=-\left(x+1\right)\)

Thay vào (*), ta có:

\(-x-1=\)\(-2-2x\)

\(\Leftrightarrow-x+2x=-2+1\)

\(\Leftrightarrow x=-1\)(kTMĐK)

Vậy S\(=\){-1}

b, \(x^2-6x+9=1\)

\(\Leftrightarrow x^2-2.3.x+3^2\)

\(\Leftrightarrow\left(x-3\right)^2=1\)

\(\Leftrightarrow\left(x-3\right)^2-1^2=0\)

\(\Leftrightarrow\left(x-3-1\right)\left(x-3+1\right)=0\)

\(\Leftrightarrow\left(x-4\right)\left(x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=2\end{matrix}\right.\)

Vậy S\(=\){4;2}

=6x+1(1)

TH1: Nếu x+2 \(\ge\)0 \(\Leftrightarrow\)x\(\ge\)-2 \(\Rightarrow\)|x+2|=x+2

Thay vào (1) ta có:

x+2 = 6x + 1

\(\Leftrightarrow\)x-6x=1-2

\(\Leftrightarrow\)-5x=-1

\(\Leftrightarrow\)x= \(\dfrac{1}{5}\)(TMĐK)

TH2: Nếu x+2\(\le\)0 \(\Leftrightarrow\)x < -2 \(\Rightarrow\)|x+2| = -(x+2)

Thay vào (1) ta có:

-x-2=6x+1

\(\Leftrightarrow\)-x-6x=1+2

\(\Leftrightarrow\)-7x=3

\(\Leftrightarrow\)x=\(-\dfrac{3}{7}\)(KTMĐK)

Vậy S={\(\dfrac{1}{5}\)}