\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\dfrac{1}{2}\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\dfrac{1}{2}\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\dfrac{1}{2}\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\dfrac{1}{2}\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(P=\dfrac{1}{2}\left(5^{32}-1\right)\)

\(P=\dfrac{5^{32}-1}{2}\)

Code greas

Iternet

Date a live.

Thất tình đại tội

Code greas

Strike the blood

Quy trình chế biến sữa đậu nành bao gồm mấy bước ?

A. 2 : 1

B. 3 : 1

C. 5 : 2

D. 1 : 3

\(\text{a) }\left(x-1\right)\left(x+1\right)\left(x+2\right)\\ =\left(x^2-1\right)\left(x+2\right)\\ =x^2\left(x+2\right)-\left(x+2\right)\\ =x^3+2x^2-x-2\)

\(\text{b) }\dfrac{1}{2}x^2y^2\left(2x+y\right)\left(2-y\right)\\ =\dfrac{1}{2}x^2y^2\left(4x^2-y^2\right)=2x^4y^2-\dfrac{1}{2}x^2y^4\)

Câu 2 bạn thay vào mà làm nhé. Mình ngại lắm

Câu 1:

\(\text{a) }x^3+y^3+z^3-3xyz=\left(x+y+z\right)\left(x^2+y^2+z^2-3xy-3yz-3xz\right)\)

\(\text{b) }x^6-y^6=\left(x^3\right)^2-\left(y^3\right)^2=\left(x^3-y^3\right)\left(x^3+y^3\right)=\left(x-y\right)\left(x^2+xy+y^2\right)\left(x+y\right)\left(x^2-xy+y^2\right)\)

\(\text{c) }xy\left(x+y\right)+yz\left(y+z\right)+xz\left(x+z\right)+2xyz\\ =x^2y+xy^2+y^2z+yz^2+x^2z+xz^2+xyz+xyz\\ =\left(x^2y+x^2z+xyz\right)+\left(xy^2+y^2z+xyz\right)\\ =x\left(xy+xz+yz\right)+y\left(xy+yz+xz\right)\\ =\left(x+y\right)\left(xy+yz+xz\right)\\ \\ \)

Câu 3:

\(x^2-10x=-25\\ \Leftrightarrow x^2-10x+25=0\\\Leftrightarrow\left(x-5\right)^2=0\\ \Leftrightarrow x-5=0\\ \Leftrightarrow x=5 \)

Vậy \(x=5\)

\(\)