HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
Give the correct forms or tenses of the verbs in brackets:
1, Does she usually work (work) ten hours a day?
2, She started (start) painting in 1980.
3, He is an awful driver. He never stops (stop) the car smoothly.
4, When Peter was young, he (like) liked to drink coffee.
Word forms:
1. We usually go swimming in the morning. (SWIM)
2. She looks more beautiful than her sister. (BEAUTY)
3. Stop, Nam! It's dangerous to be near the stove. (DANGER)
4. Their childen have quite different character. (DIFFERENCE)
5. My father likes sky. (SKY)
''I don't understand what you are saying'' She said to me.
=> She said me that she didn't understand what I was saying.
Chọn từ có trọng âm khác vs các từ còn lại:
1. A. camera B.finally C. vacation D. idea
2. A. vacation B. collect C. desert D. destroy
3. A. favorite B. lemonade C. chocolate D. interesting
4. A. natural B. tomorrow C. behind D. banana
- Câu 1 vs câu 2 hình như sai đề =33
- Ko dùng "by her" và "by us" :3
3x=2y
=>x/2=y/3=>x/10=y/15 (1)
4y=5z
=>y/5=z/4=>y/15=z/12 (2)
từ 1 và 2
=>x/10=y/15=z/12
áp .. ta có:
x/10=y/15=z/12=x+y-z/10+15-12=78/13=6
=>x/10=6=>x=60
=>y/15=6=>y=90
=>z/12=6=>z=72
\(a,ĐKXĐ:x\ge0;x\ne9;x\ne4\)
\(b,C=\left(\dfrac{x-9-x+3\sqrt{x}}{x-9}\right):\left(\dfrac{\sqrt{x}-2}{\sqrt{x}+3}-\dfrac{\sqrt{x}-3}{\sqrt{x}-2}-\dfrac{9-x}{x+\sqrt{x}-6}\right)\\ =\left(\dfrac{3\sqrt{x}-9}{x-9}\right):\)
\(\left(\dfrac{\left(\sqrt{x}-2\right)^2-\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)-9+x}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}\right)\\ =\left(\dfrac{3\left(\sqrt{x}-3\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\right):\left(\dfrac{x-4\sqrt{x}+4-x+9-9+x}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}\right)\\ =\dfrac{3}{\sqrt{x}+3}.\dfrac{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}{x-4\sqrt{x}+4}\\ =\dfrac{3\left(\sqrt{x}-2\right)}{\left(\sqrt{x}-2\right)^2}\\ =\)
200=2^3.5^2 có công thức tỉm số ước là;(số mũ số thứ nhất +1)(số mũ số thứ 2 +1)
vậy 200 có số ước là;(3+1)(2+1)=12(ước)
The English teacher who teaches us writing and reading comes London.
\(a,A=5\sqrt{10}-10-5\sqrt{10}\\ =-10\\ b,B=2\sqrt{3}+3\sqrt{3}-\dfrac{\sqrt{3}+1}{2}\\ =5\sqrt{3}-\dfrac{\sqrt{3}+1}{2}\\ =\dfrac{10\sqrt{3}-\sqrt{3}-1}{2}\\ =\dfrac{9\sqrt{3}-1}{2}\)