Bài 2

d)

\(=\frac{\sqrt{3\left(x-3\right)}}{\sqrt{\left(\sqrt{x}\right)^2-\sqrt{3}^2}}=\frac{\sqrt{3\left(x-3\right)}}{\sqrt{x-3}}=\sqrt{3}\)

Bài 2c

\(=\frac{\sqrt{\left(\sqrt{a}-\sqrt{b}\right)^2}}{\sqrt{\sqrt{a}-\sqrt{b}}}=\frac{\sqrt{a}-\sqrt{b}}{\sqrt{\sqrt{a}-\sqrt{b}}}\)

\(=\sqrt{\sqrt{a}-\sqrt{b}}\)

49 phải ko

1. ông thọ 

2. 90 + 20 =110

các bạn tk cho mk đi nha.

thank you.

happy new year.

Đáp Án 327500

tk đi rồi mk làm cho

Gọi số cần tìm là ab

Ta có:1ab1=23ab

1000+10ab+1=23ab

1001+10ab=23ab

1001=13ab

ab=1001:13

ab=77

Vậy số duy nhất thỏa mãn đề bài là 77.

b)

\(=\left(b^2c+bc^2+c^2a+abc\right)-\left(ca^2+a^2b+ab^2+abc\right)\)

\(=c\left(b^2+bc+ca+ab\right)-a\left(ca+ab+b^2+bc\right)\)

\(=\left(c-a\right)\left[\left(ca+ab\right)+\left(b^2+bc\right)\right]\)

\(=\left(a+b\right)\left(b+c\right)\left(c-a\right)\)

a) \(=a^2b-ab^2+b^2c-bc^2+a^2c-ac^2\)

\(=abc+a^2b-ab^2+b^2c-bc^2+a^2c-ac^2-abc\)

\(=ab\left(a-c\right)-b^2\left(a-c\right)-c^2\left(a-c\right)-ac\left(a-c\right)\)

\(=\left[b\left(a-b\right)\left(a-c\right)\right]-\left[c\left(a-b\right)\left(a-c\right)\right]\)\(=\left(a-b\right)\left(b-c\right)\left(c-a\right)\)