\(\dfrac{y+z-x}{x}=\dfrac{z+x-y}{y}=\dfrac{x+y+z}{z}\)

\(\Rightarrow\dfrac{y+z-x}{x}+2=\dfrac{z+x-y}{y}+2=\dfrac{x+y-z}{z}+2=\)

\(\dfrac{y+z+x}{x}=\dfrac{z+x+y}{y}=\dfrac{x+y+z}{z}\)

\(\Rightarrow\)x=y=z\(\Rightarrow\)\(\dfrac{x}{y}=\dfrac{y}{z}=\dfrac{z}{x}=1\)

\(\Rightarrow\)B=(1+1)(1+1)(1+1)=8

1007

4

12

48

67

2017

18

2

10

10

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