Bài làm 2:

Theo đề bài, ta có:

\(\dfrac{3x}{4}\)=\(\dfrac{y}{2}\)=\(\dfrac{3z}{5}\) biết y-z=15

=>\(\dfrac{3x}{4}\)=\(\dfrac{y}{2}\)=\(\dfrac{z}{\dfrac{5}{3}}\)

Áp dụng t/c dãy tỉ số = nhau, ta có:

\(\dfrac{3x}{4}\)=\(\dfrac{y}{2}\)=\(\dfrac{\dfrac{z}{5}}{3}\)=\(\dfrac{y-z}{2-\dfrac{5}{3}}\)=\(\dfrac{15}{\dfrac{1}{3}}\)=45

=>3x=180=>x=60

y=90

z=75

x+y+z=60+90+75=225

Vòng thi thứ mấy vậy bạn @Lê Đức Trung Hiếu?

a) \(\dfrac{x}{15}\)=\(\dfrac{x-2}{30}\)

=>30x=15 (x-2)

=>30x=15x-30

=>30x-15x=-30

=>15x =-30

=>x =-2

b)\(\dfrac{7}{8}\)<\(\dfrac{x}{80}\)<\(\dfrac{9}{10}\)

=>\(\dfrac{70}{80}\)<\(\dfrac{x}{80}\)<\(\dfrac{72}{80}\)

=> 70<x<72

=>x=71

c)\(\dfrac{1}{6}\)<\(\dfrac{5}{x}\)<\(\dfrac{1}{4}\)

=>\(\dfrac{5}{30}\)<\(\dfrac{5}{x}\)<\(\dfrac{5}{20}\)

=>20<x<30

=>x={21;22;23;24;25;26;27;28;29}