b, = \(\frac{\sqrt{5}}{\sqrt{6}}=\frac{\sqrt{5}.\sqrt{6}}{\left(\sqrt{6}\right)^2}=\frac{\sqrt{30}}{6}\)

b, = \(\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{3+2\sqrt{6}+2+5}-\frac{\sqrt{3}+\sqrt{2}-\sqrt{5}}{3+2\sqrt{6}+2+5}=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{2\sqrt{6}}-\frac{\sqrt{3}+\sqrt{2}-\sqrt{5}}{2\sqrt{6}}=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}-\sqrt{3}-\sqrt{2}+\sqrt{5}}{2\sqrt{6}}=\frac{2\sqrt{5}}{2\sqrt{6}}\)

b. = \(\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{\left(\sqrt{3}+\sqrt{2}+\sqrt{5}\right)\left(\sqrt{3}+\sqrt{2}-\sqrt{5}\right)}-\frac{\sqrt{3}+\sqrt{2}-\sqrt{5}}{\left(\sqrt{3}+\sqrt{2}+\sqrt{5}\right)\left(\sqrt{3}+\sqrt{2}-\sqrt{5}\right)}=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}}{\left(\sqrt{3}+\sqrt{2}\right)^2-\left(\sqrt{5}\right)^2}-\frac{\sqrt{3}+\sqrt{2}-\sqrt{5}}{\left(\sqrt{3}+\sqrt{2}\right)^2-\left(\sqrt{5}\right)^2}\)

a, = \(=\frac{\sqrt{7}-5}{2}-\frac{3-\sqrt{7}}{2}+\frac{6\sqrt{7}+12}{7-4}-\frac{20-5\sqrt{7}}{16-7}=\frac{\sqrt{7}-5-3+\sqrt{7}}{2}+\frac{6\sqrt{7}+12}{3}-\frac{20-5\sqrt{7}}{9}\)

\(\frac{4}{25}=0,16=16\%\)