110

bang cuu chuong so 8 ai ma cha biet

có

\(\left(x^2-16\right)\left(x^2-3x-4\right)=0< =>\left(x-4\right)\left(x+4\right)\left(x^2-4x+x-4\right)=0< =< \left(x-4\right)\left(x+4\right)\left[x\left(x-4\right)+\left(x-4\right)\right]=0< =>\left(x-4\right)^2\left(x+4\right)\left(x+1\right)=0< =>\left[{}\begin{matrix}x-4=0\\x+4=0\\x+1=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=4\\x=-4\\x=-1\end{matrix}\right.\)

cua xanh

45 cm

tick nhe

bạn nói rõ hơn 1 tí đi

\(x^2+5x+6=0< =>x^2+2x+3x+6=0< =>x\left(x+2\right)+3\left(x+2\right)=0< =>\left(x+3\right)\left(x+2\right)=0< =>\left[{}\begin{matrix}x+2=0\\x+3=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=-2\\x=-3\end{matrix}\right.\)