cái j vậy

Ta có: 2⁶⁰³=(2³)²⁰¹=8²⁰¹; 3⁴⁰²=(3²)²⁰¹=9²⁰¹

Vì 8<9 nên 2⁶⁰³<3⁴⁰²

A

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Câu hỏi của Hà Phương - Toán lớp 8 - Học toán với OnlineMath

bé hơn hoặc bằng chứ sai dấu rồi bạn

\(\left(x+3\right)\left(6-2x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\6-2x=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0-3\\-2x=0-6\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0-3\\-2x=-6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=3\end{matrix}\right.\)

Vậy \(x_1=-3;x_2=3\)

\(8x^3+12x^2y+6xy^2+y^3 \)

\(=2x^3 + 3.2x^2.y + 3.2x.y^2 + y^3\)

\(=(2x+y)^3\)

a) \(0,5\cdot\left(x-\dfrac{1}{3}\right)-\dfrac{1}{2}=x+\left(-\dfrac{4}{5}\right)\)

\(\Rightarrow\dfrac{1}{2}\cdot\left(x-\dfrac{1}{3}\right)-\dfrac{1}{2}=x-\dfrac{4}{5}\)

\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{1}{6}-\dfrac{1}{2}=x-\dfrac{4}{5}\)

\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{2}{3}=x-\dfrac{4}{5}\)

\(\Leftrightarrow15x-20=30x-24\)

\(\Leftrightarrow15x-30x=-24+20\)

\(\Leftrightarrow-15x=-4\)

\(\Rightarrow x=\dfrac{4}{15}\)

Vậy \(x=\dfrac{4}{15}\)

b) \(\dfrac{2}{3}\cdot\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)+\dfrac{1}{2}=\dfrac{2}{3}-x\)

\(\Rightarrow\dfrac{1}{3}x-\dfrac{2}{9}+\dfrac{1}{2}=\dfrac{2}{3}-x\)

\(\Leftrightarrow\dfrac{1}{3}x+\dfrac{5}{18}=\dfrac{2}{3}-x\)

\(\Leftrightarrow6x+5=12-18x\)

\(\Leftrightarrow6x+18x=12-5\)

\(\Leftrightarrow24x=7\)

\(\Rightarrow x=\dfrac{7}{24}\)

Vậy \(x=\dfrac{7}{24}\)