HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
Tuyển Cộng tác viên Hoc24 nhiệm kì 28 tại đây: https://forms.gle/GrfwFgzveoKLVv3p6
Tổng tổi của 2 bố con là :
25 * 2 = 50 ( tuổi )
Tuổi bố là :
( 50 + 28 ) : 2 = 39 ( tuổi )
Đ/S: 39 tuổi
giúp mik gấp nhé(thanks)exercise 4: give the correct word form1.Today Lien is unhappy (happy)because she misses her parents2.Nam's new house is bigger (big) than his old house3. There are 32 classes ( class) in our school4. He doesn't have many relatives ( relate) in Ha Noi5.They are talking (talk) to their teacherexercise 5:rewrite the sintences.1. It is a good idea to eat a lot of fruit and vegetable everydayWe should eat a lot of fruit and vegetable everyday.2. we couldn't keep on cleaning the streets because of the heavy rainBecause of the heavy rain, we couldn't keep on cleaning the streets3.The garden party won't take place if the weather doesn't improveUnless the weather improves, the garden party won't take place.4.both students and teachers can borrow books from the libralyThe library lend both students and teachers the books5.nobody plays this piece of music as beautifully as he doesHe plays this piece of music the most beautifully.6.there is a sink, a tub, and a shower in the bathroomThe bathroom has sink, a tub, and a shower.7.no one in the group is taller than TrungTrung is the tallest one in the group.8.Do you have a better refrigerator than thisIs this the best refrigerator you have?
\(E=\frac{n^2+n+1}{n+1}=\frac{n^2}{n+1}+\frac{n+1}{n+1}=\frac{n^2}{n+1}+1\)
=> \(\frac{n^2}{2+1}\in Z\)
Có: \(n^2\) chia hết cho \(n\) suy ra \(n^2\) không chia hết cho \(n+1\)
Do đó: \(n=0\)
Mặt khác: Để E thuộc Z
=> n+1 = -1 => n = -2
a) \(x^3-x^2-5x+125\)
\(=\left(x+5\right)\left(x^3-5x+25\right)-x\left(x+5\right)\)
\(=\left(x+5\right)\left(x^3-5x+25-x\right)\)
\(=\left(x+5\right)\left(x^3-6x+25\right)\)
CHÂU ÂU NẰM Ở ĐÂU???.BẠN
NÀO BIẾT TRẢ LỜI GIÚP MÌNH NHA
b) \(x^3+2x^2-6x-27\)
\(=\left(x-3\right)\left(x^3+3x+9\right)+2x\left(x-3\right)\)
\(=\left(x-3\right)\left(x^3+3x+9+2x\right)\)
\(=\left(x+3\right)\left(x^3+5x+9\right)\)
\(=\left(5+x\right)\left(25-5x+x^2\right)-x\left(5+x\right)\)
\(=\left(5+x\right)\left(25-5x+x^2-x\right)\)
\(=\left(5+x\right)\left(25-4x+x^2\right)\)
yx99=30,25-10
yx99=20,25
y=20,25:99
y=0,20(45)
ta thấy 10+16=26
16+26=42
=> số đằng sau bằng tổng của hai số đằng trước cộng lại
ta có 16-10=6
nên số trước 10 là 6
ta có 10-6=4
nên số trước 6 là 4
ta có 6-4=2
nên số trước 4 là 2
vậy số đầu là 2