nguồn : olm : mìh đã sớt rồi :))

sớt gg sẽ có

\(A=\frac{100^{2007}+1}{100^{2009}+1}=\frac{100^{2009}+1-100^2}{100^{2009}+1}=1-\frac{100^2}{100^{2009}+1}\)

\(B=\frac{100^{2005}+1}{100^{2007}+1}=\frac{100^{2007}+1-100^2}{100^{2007}+1}=1-\frac{100^2}{100^{2007}+1}\)

=> A>B