A=\(\dfrac{3\sqrt{x}-6}{x-2\sqrt{x}}+\dfrac{\sqrt{x}-3}{\sqrt{x}}-\dfrac{1}{2-\sqrt{x}}\) và B=\(\dfrac{\sqrt{x}-2}{\sqrt{x}+9}\)
Cho P=A.B. Tìm số nguyên x để \(\sqrt{P}< \dfrac{1}{3}\)

\(\sqrt{3x^2-7x+3}-\sqrt{x^2-2}=\sqrt{3x^2-5x-1}-\sqrt{x^2-3x+4}\)

\(\sqrt{5x+4}+\sqrt{3x+2}=\sqrt{4x+5}+\sqrt{2x+3}\)

\(\sqrt{3-x}=3x-5\)

M=cot28\(^o\).cot62\(^o\)+tan60\(^o\)

c)\(\sqrt[3]{x-1}+1=x\)
d)\(\sqrt[3]{x^3+9^2}=x+3\)

(\(\left(\sqrt[3]{9}+\sqrt[3]{6}+\sqrt[3]{4}\right)\left(\sqrt[3]{3}+\sqrt[3]{2}\right)\)

A=\(\sqrt[3]{2+\sqrt{5}}+\sqrt[3]{2-\sqrt{5}}\)

A=\(\dfrac{\sqrt[3]{384}}{\sqrt[3]{3}}+3\sqrt[3]{-54}+\sqrt[3]{432}\)

Tính giá trị biểu thức: A=2 tan\(32^0\).tan\(58^o\) - si\(n^2\) \(24^o\) - sin² \(66^o\)