Nhảm nhí!

Thời gian ô tô đi từ A đến B:

11 giờ - 8 giờ 30 phút = 2 giờ 30 phút = 2,5 giờ

Độ dài quãng đường AB là:

\(48\times2,5=120\left(km\right)\)

\(-x=0\)

tức là \(\left(-1\right).x=0\)

\(\Leftrightarrow\left(-1\right).x:\left(-1\right)=0:\left(-1\right)\)

\(\Leftrightarrow x=0\)

\(-x=0\)

\(\Leftrightarrow x=0\)

\(\dfrac{2}{5}\) của \(15=\dfrac{2}{5}\times15=6\)

\(75\%:2\dfrac{1}{5}+\left(0,5\right)^2.\left(-7\right)+2,5\left(7\dfrac{2}{3}+5\dfrac{2}{3}\right)\)

\(=\dfrac{3}{4}:\dfrac{11}{5}+\dfrac{1}{4}.\left(-7\right)+2,5\left(12+\dfrac{4}{3}\right)\)

\(=\dfrac{15}{44}-\dfrac{7}{4}+\dfrac{5}{2}.\dfrac{40}{3}\)

\(=-\dfrac{31}{22}+\dfrac{100}{3}\)

\(=\dfrac{2107}{66}\)

Giải rồi đó em!

Var a:array[1..1000] of integer;

i,n,max:integer;

Begin

Write('n = ');readln(n);

For i:=1 to n do

Begin

Write('Nhap phan tu thu ',i);readln(a[i]);

End;

max:=a[1];

for i:=2 to n do

if max < a[i] then max:=a[i]

write('So lon nhat trong day la ',max);

Readln

End.

\(\dfrac{3}{2}\times\dfrac{4}{5}-x=\dfrac{2}{3}\)

\(\dfrac{6}{5}-x=\dfrac{2}{3}\)

\(x=\dfrac{6}{5}-\dfrac{2}{3}\)

\(x=\dfrac{8}{15}\)

-------------------------------------

\(x+x\times\dfrac{7}{8}+x\times\dfrac{9}{2}=255\)

\(x\times\left(1+\dfrac{7}{8}+\dfrac{9}{2}\right)=255\)

\(x\times\dfrac{51}{8}=255\)

\(x=255:\dfrac{51}{8}\)

\(x=40\)