HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
\(1,=-0,8.\left|-0,125\right|=-0,8.0,125=-0,1\\ ----------\\ 3,=\left|4+\sqrt{2}\right|=4+\sqrt{2}\\ ----------\\ 5,=\left|4-\sqrt{17}\right|=\sqrt{17}-4\)
\(5x-3\left[4x-2\left(4x-15x+6\right)\right]=182\\ 5x-3\left[4x-2\left(-11x+6\right)\right]=182\\ 5x-3\left(4x+22x-12\right)=182\\ 5x-78x+36=182\\ -73x=146\\ x=-2\)
\(a,x:\dfrac{1}{2}=\dfrac{3}{5}\\ x=\dfrac{3}{5}\times\dfrac{1}{2}\\ x=\dfrac{3}{10}\\ ----------\\ b,x\times\dfrac{1}{3}=\dfrac{4-3}{4}\\ x\times\dfrac{1}{3}=\dfrac{1}{4}\\ x=\dfrac{1}{4}:\dfrac{1}{3}\\ x=\dfrac{1}{4}\times\dfrac{3}{1}\\ x=\dfrac{3}{4}\)
\(a,x=\dfrac{1}{3}:\dfrac{1}{2}\\ x=\dfrac{1}{3}.\dfrac{2}{1}\\ x=\dfrac{2}{3}\\ ----------\\ b,x=\dfrac{5}{2}\times\dfrac{4}{5}\\ x=\dfrac{4}{2}=2\\ ----------\\ c,x=\dfrac{2}{9}:\dfrac{2}{3}\\ x=\dfrac{2}{9}\times\dfrac{3}{2}\\ x=\dfrac{3}{9}=\dfrac{1}{3}\)
\(1,\\ a,=8^2.6^3.7^3=\left(2^3\right)^2.2^3.3^3.7^3=2^9.3^3.7^3\\ b,=8^2.10.5^2.2^4=\left(2^3\right)^2.2^4.2.5.5^2=2^{11}.5^3\)
Chiều rộng HCN là :
\(\dfrac{3}{10}:\dfrac{3}{4}=\dfrac{2}{5}\left(m\right)\)
Chu vi HCN là :
\(\left(\dfrac{3}{4}+\dfrac{2}{5}\right)\times2=\dfrac{23}{10}\left(m\right)\)
\(a,=\dfrac{1\times3\times5}{3\times5\times9}=\dfrac{1}{9}\\ ----------\\ b,=\dfrac{15}{16}\times\dfrac{8}{3}\times\dfrac{3}{4}=\dfrac{15\times8\times3}{16\times3\times4}=\dfrac{15}{8}\)