HOC24
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`(6)/(18)+(-14)/(21)`
`=(6:6)/(18:6)-(14:7)/(21:7)`
`=(1)/(3)-(2)/(3)`
`=(1-2)/(3)=-1/3`
`x=1+2+4+...+2^{2002}+2^{2003}`
`=1+2^{1}+2^{2}+2^{3}+...+2^{2002}+2^{2003}`
`=>2x=2^{1}+2^{2}+2^{3}+2^{4}+...+2^{2003}+2^{2004}`
`=>2x-x=(2^{1}+2^{2}+2^{3}+2^{4}+...+2^{2003}+2^{2004})-(1+2^{1}+2^{2}+2^{3}+...+2^{2002}+2^{2003})`
`=>x=2^{2004}-1`
`=>x+1=2^{2004}=y` (DPCM)
`(a):\sqrt{2x-5}=\sqrt{x-1}\ (ĐK:x\ge 5/2)`
`<=>2x-5=x-1`
`<=>2x-x=5-1`
`<=>x=4(TMDK)`
Vậy `S={4}`
`(b):x^{2}-2=x-2\sqrt{x+1}\ (ĐK:x\ge -1)`
`<=>x^{2}=x+1-2.\sqrt{x+1}.1+1^{2}`
`<=>x^{2}=(\sqrt{x+1}-1)^{2}`
`<=>|x|=|\sqrt{x+1}-1|`
`=>x=\sqrt{x+1}-1\ (1)` hoặc `x=-\sqrt{x+1}+1\ (2)`
`(1)<=>x+1=\sqrt{x+1}`
`<=>x^{2}+2x+1=x+1` `(ĐK:x\ge -1)`
`<=>x^{2}+x=0`
`<=>x(x+1)=0`
`=>x=0` hoặc `x=-1` (TMDK)
`(2)<=>\sqrt{x+1}=1-x`
`<=>x+1=x^{2}-2x+1` `(ĐK:1-x\ge0;x\ge -1<=>-1\le x\le 1)`
`<=>x^{2}-3x=0`
`<=>x(x-3)=0`
`=>x=0\ (TMDK)` hoặc `x=3\ (KTMDK)`
Vậy `S={0;-1}`
Tổng chiều dài và rộng là :
`72:2=36(cm)`
Chiều rộng là :
`36-20=16(cm)`
`x^{2}-21x+38=(x^{2}-2x)-(19x-38)`
`=x(x-2)-19(x-2)`
`=(x-2)(x-19)`
`(a):(5\sqrt{2}+\sqrt{10})/(\sqrt{5}+1)+(12)/(4-\sqrt{10})-8\sqrt{(5)/(2)}`
`=(\sqrt{25.2}+\sqrt{10})/(\sqrt{5}+1)+(12(4+\sqrt{10}))/((4+\sqrt{10})(4-\sqrt{10}))-\sqrt{(64.5)/(2)}`
`=(\sqrt{10}.(\sqrt{5}+1))/(\sqrt{5}+1)+(12(4+\sqrt{10}))/(16-10)-\sqrt{160}`
`=\sqrt{10}+2(4+\sqrt{10})-4\sqrt{10}`
`=\sqrt{10}+8+2\sqrt{10}-4\sqrt{10}`
`=8-\sqrt{10}`
`(b):(\sqrt{3}+4)/(5-2\sqrt{3})-(5\sqrt{3}-3)/(\sqrt{3})+6\sqrt{1/3}`
`=((\sqrt{3}+4)(5+2\sqrt{3}))/((5-2\sqrt{3})(5+2\sqrt{3}))-(\sqrt{3}(5-\sqrt{3}))/(\sqrt{3})+\sqrt{(36)/(3)}`
`=(26+13\sqrt{3})/(25-12)-(5-\sqrt{3})+\sqrt{12}`
`=(13(2+\sqrt{3}))/(13)-5+\sqrt{3}+2\sqrt{3}`
`=2+\sqrt{3}-5+\sqrt{3}+2\sqrt{3}`
`=4\sqrt{3}-3`
`x^{2}+4x-21=(x^{2}-3x)+(7x-21)`
`=x(x-3)+7(x-3)`
`=(x-3)(x+7)`
`(c):` Để `(d)` cắt `(d'')` thì :
`a\ne a''`
`<=>m-3\ne 1`
`<=>m\ne 4`
`(d):` Để `(d)` \(\perp\) `(d''')` thì :
`a.a'''=-1`
`<=>(m-3).(1)/(2)=-1`
`<=>m-3=(-1):(1)/(2)=-2`
`<=>m=1`
`(-300):20+5.(3x-1)=25`
`=>-15+15x-5=25`
`=>15x-20=25`
`=>15x=25+20=45`
`=>x=45/15=3`
`axx(b+c)=axxb+axxc`
`axx(b-c)=axxb-axxc`