HOC24
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a, 15 : (x+2) = (\(3^3\)+3) : 10
b, 65 - \(4^{x+2}\) = 20140
B=\(\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\) C= \(\dfrac{4^5.9^4-2.6^4}{2^{10}.3^8+6^8.20}\)
a, A= \(\dfrac{4^5.9^4-4.3^{20}.8^9}{5.2^{10}.6^{12}-7.2^{29}.27^6}\)
b, B=\(\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\)
c, C=\(\dfrac{4^5.9^4-2.6^4}{2^{10}.3^8+6^8.20}\)