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=> 5x + 1 = 4^2 = 16

=> 5x = 15

=> x = 3

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đk x khác 1/2 ; -1/2 A = ( 2 x + 1 ) 2 − ( 2 x − 1 ) 2 4 x 2 − 1 : 4 x 5 ( 2 x − 1 ) = ( 2 x + 1 − 2 x + 1 ) ( 2 x + 1 + 2 x − 1 ) 4 x 2 − 1 : 4 x 5 ( 2 x − 1 ) = 8 x .5 ( 2 x + 1 ) .4 x = 10 2 x + 1 2, đk x khác 2;-2 3, đk x khác 1 P = x : ( x 2 − 1 − x 2 − x − 1 + x 2 + 2 x 3 − 1 ) = x : ( x 2 − x x 3 − 1 ) = x : ( x x 2 + x + 1 ) = x 2 + x + 1

A=

A=

A=3+

=>x=6,1