\(\dfrac{x}{3}-\dfrac{2x+1}{6}=\dfrac{x}{6}-x\)

\(\Leftrightarrow\dfrac{2x-\left(2x+1\right)}{6}=\dfrac{x-6x}{6}\)

\(\Leftrightarrow2x-2x-1=x-6x\)

\(\Leftrightarrow-5x=-1\)

\(\Leftrightarrow x=\dfrac{1}{5}\)

Vậy \(S=\left\{\dfrac{1}{5}\right\}\)

hihi:)) tạo cho zuii cj:v

hơ hơ câu 3 hồi nãy mũ 3 bạn viết mũ 2:v

:D e bên Hóa+Toán ý:v

\(\dfrac{x+4}{5}-x+4=\dfrac{x}{3}-\dfrac{x-2}{2}\)

\(\Leftrightarrow\dfrac{6\left(x+4\right)+30\left(4-x\right)}{30}=\dfrac{10x-15\left(x-2\right)}{30}\)

\(\Leftrightarrow6\left(x+4\right)+30\left(4-x\right)=10x-15\left(x-2\right)\)

\(\Leftrightarrow6x+24+120-30x=10x-15x+30\)

\(\Leftrightarrow-19x=-114\)

\(\Leftrightarrow x=6\)

Vậy \(S=\left\{6\right\}\)