b.     \(\dfrac{x+4}{5}-x+4=\dfrac{x}{3}-\dfrac{x-2}{2}\)

   ⇔ \(\dfrac{x+4}{5}-x+\dfrac{4}{1}=\dfrac{x}{3}-\dfrac{x-2}{2}\)

   ⇔ \(\dfrac{x+24}{5}-x=\dfrac{x}{3}-\dfrac{x-2}{2}\)

   ⇔  \(6\left(x+24\right)-30x=-5x+30\)

   ⇔  \(-24x+5x=30-144\)

   ⇔ \(19x=114\)

   ⇔ \(x=114:9\)

   ⇔ \(x=6\)

a.    7 + 2x = 32 - 3x

<=> 2x + 3x = 32 - 7

<=> 5x = 25

<=> x = 5