anh xài app Geodebra vẽ đi ạ :000

\(5x+11=0\\ 5x=-11\\ x=-\dfrac{11}{5}\)

\(b,\dfrac{1}{20}+\dfrac{3}{4}+\dfrac{6}{5}\\ =\dfrac{1}{20}+\dfrac{15}{20}+\dfrac{24}{20}\\ =\dfrac{40}{20}=2\\ c,\dfrac{3}{4}+\dfrac{1}{25}+\dfrac{1}{100}\\ =\dfrac{75}{100}+\dfrac{4}{100}+\dfrac{1}{100}=\dfrac{80}{100}=\dfrac{4}{5}\\ d,=\dfrac{2}{25}+\dfrac{3}{25}+\dfrac{35}{25}=\dfrac{41}{25}\)

\(\sqrt{\dfrac{\left(x-2\right)^4}{\left(3-x\right)^2}}+\dfrac{x^2-1}{x-3}\\ =\dfrac{\left(x-2\right)^2}{x-3}+\dfrac{x^2-1}{x-3}=\dfrac{x^2-4x+4+4+x^2-1}{x-3}=\dfrac{2x^2-4x+3}{x-3}\)

Thay `x=0,5` vào biểu thức , ta có :

\(\dfrac{2\cdot0,5^2-4\cdot0,5+3}{0,5-3}=-\dfrac{3}{5}\)

\(11\times\left(y-6\right)=4\times y+11\\ \Rightarrow11\times y-11\times6=4\times y+11\\ \Rightarrow11\times y-4\times y=11+11\times6\\ \Rightarrow y\times\left(11-4\right)=11\times7\\ \Rightarrow y\times7=77\\ \Rightarrow y=11\)

;v để câu khác đi 

:) nope 

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