HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
\(b,=\left(x^2-5xy\right)-\left(x-5y\right)\)
\(=x\left(x-5y\right)-\left(x-5y\right)\)
\(\left(x-5y\right)\left(x-1\right)\)
a,
\(mH_2S=0,4.34=13,6\left(gam\right)\):,\(VH_2S\left(đktc\right)=22,4.0,4=8,96lít\)
\(mSO_2=0,025.64=1,6\left(gam\right)\);\(VSO_2=22,4.0,025=0,56l\)
PTHH:
\(Mg+2HCl\rightarrow MgCl_2+H_2\)
\(mCuO=n.M=2,5.80=200\left(gam\right)\)
b,
\(nCO_2=\dfrac{4,48}{22,4}=0,2\left(mol\right)\)
c,\(mSO_2=n.M=\left(4,48:22,4\right).64=12,8\left(gam\right)\)
d, ct hỗn hợp khí: \(H_2O_2\)
\(mH_2O_2=\left[\left(11,2:22,4\right).2\right]+\left[\left(5,6:22,4\right).32\right]\)
\(mH_2O_2=9\left(gam\right)\)
hợp chất: \(NH_3,CO_2,C_2H_2,C_2H_4\)
\(d_{\dfrac{H2}{H2}}=\dfrac{2}{2}=1\)
\(d_{\dfrac{N2}{H2}}=\dfrac{14.2}{2}=14\)
\(d_{\dfrac{O2}{H2}}=\dfrac{16.2}{2}=16\)
c,
\(d_{\dfrac{NH3}{kk}}=\dfrac{17}{29}=1\)
\(d_{\dfrac{CO}{kk}}=\dfrac{28}{29}=1\)
\(d_{\dfrac{CO2}{kk}}=\dfrac{44}{29}=2\)
\(d_{\dfrac{C2H2}{kk}}=\dfrac{26}{29}=1\)
\(d_{\dfrac{C2H4}{kk}}=\dfrac{28}{29}=1\)
b,=(x+3y-3y(x+3y+3y)
= x(x+6y)
a, MSO3=32+16.3=80g/mol
%S=\(\dfrac{32.100}{80}=40\%\)
%O=\(\dfrac{16.3.100}{80}=60\%\)