HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
1,We have repaired the bike at 6:30 pm
2, He has eaten at 7 pm.
3, They have worked at 8 :00
4, She is interested in cooking
5, It's such a fat cat that it walks slowly
6, It's such hot weather that I don't want to go out
7, It was such a beautiful cake that I didn't want to eat.
She told me if I studied carefully, I would answers those questions well.
19, Jean cloth was made completely from cotton in the \(18^{th}\) century
20, You can write an English letter, can't you?
21, The last time everybody saw Tom was a week ago.
22, The English test will be taken by all the students of the ninth form next week.
23, Our teeth should be brushed carefully after meals.
24, The traffic rules must be observed strictly
25, Their homework was done well.
26, I wish I didn't have to do homework every night.
13, How long have you known this bamboo forest?
14, She'd rather not go out late at night
15, The children are interested in the play
16, Tom's successful in doing his test.
17, This machine musn't be used after 5:30 p.m
18, Our "ao dai" can be printed lines of poetry
1,He didn't forget and neither did she
2, Despite the heavy rain, they went on travelling
3, I am so annoyed by my brother sometimes
Biện pháp tu từ : ẩn dụ (nắng mưa với những vất vả,cực nhọc)
`->` Tác dụng : tăng sức gợi hình,gợi cảm và tăng thêm giá trị biểu cảm cho câu thơ từ đó cho chúng ta thấy được sự vất vả,cực nhọc mà mẹ phải chịu đựng suốt cuộc đời
a. \(n_{Ba\left(OH\right)_2}=\dfrac{200.17,1\%}{171}=0,2\left(mol\right)\)
PTHH : Ba(OH)2 + SO2 -> BaSO3 \(\downarrow\) + H2O
0,2 0,2 0,2
b. \(m_{BaSO_3}=0.2.217=43,4\left(g\right)\)
c. \(V_{SO_2}=0,2.22,4=4,48\left(l\right)\)
\(\sqrt{7-2\sqrt{10}}-\dfrac{14}{3-\sqrt{10}}\\ =\sqrt{\left(\sqrt{5}-\sqrt{2}\right)^2}-\dfrac{14}{3-\sqrt{10}}\\ =\dfrac{\left(\sqrt{5}-\sqrt{2}\right)\left(3-\sqrt{10}\right)-14}{3-\sqrt{10}}\\ =\dfrac{3\sqrt{5}-3\sqrt{2}-5\sqrt{2}+2\sqrt{5}-14}{3-\sqrt{10}}\\ =\dfrac{5\sqrt{5}-8\sqrt{2}-14}{3-\sqrt{10}}\)
\(\left(\dfrac{\sqrt{a}}{\sqrt{a}-2}+\dfrac{\sqrt{a}}{\sqrt{a}+2}\right):\dfrac{\sqrt{4a}}{a-4}\\ =\left(\dfrac{\sqrt{a}.\left(\sqrt{a}+2\right)+\sqrt{a}.\left(\sqrt{a}-2\right)}{\left(\sqrt{a}-2\right)\left(\sqrt{a}+2\right)}\right):\dfrac{\sqrt{4a}}{a-4}\\ =\left(\dfrac{a+2\sqrt{a}+a-2\sqrt{a}}{a-4}\right):\dfrac{\sqrt{4a}}{a-4}\\ =\dfrac{2a}{a-4}.\dfrac{a-4}{\sqrt{4a}}\\ =\dfrac{2a}{2a}=1\)