D -> has

A -> requires

B -> is helping

B -> has endowed

C -> agrees

C -> has 

A -> a

C -> are required

C -> is

C -> have aroused

C -> is

A -> requires

B -> haven't

B -> was

B-> leads

B -> has

C -> was

C -> answers

A -> is

B -> was

lies

is

pass

has arrived

is

wants

was stolen

haven't finished - has

vary

is spent

go

encourages

are

are sleeping

has lived

wants

like

is

wants

disagrees

is prepared

get

is

is

has 

come

is

were cooking

were taken

am

Ex2.

Câu 1 ko có lỗi sai

C => have

D => admires

C => has to

C => is

A => brings

C => languages

C => has

C => are going to

C => was announced

a) Tứ giác ABCD có \(\widehat{B}+\widehat{ADC}=180^o\), mà \(\widehat{ADC}+\widehat{EDC}=180^o\) nên \(\widehat{B}=\widehat{EDC}\)

Xét \(\Delta ABC\) và \(\Delta EDC\) có BC=CD, AB=ED, \(\widehat{B}=\widehat{EDC}\) nên \(\Delta ABC=\Delta EDC\left(c-g-c\right)\)

b) \(\Delta ABC=\Delta EDC\Rightarrow AC=EC\) => \(\Delta ACE\) cân tại C \(\Rightarrow\widehat{CAE}=\widehat{CEA}\Rightarrow\widehat{CAD}=\widehat{CED}\) (1)

\(\Delta ABC=\Delta EDC\Rightarrow\widehat{BAC}=\widehat{CED}\) (2)

Từ (1) và (2) \(\Rightarrow\widehat{CAD}=\widehat{BAC}\)

Do đó CA là phân giác góc BAD

1B

2A

3A

4C

Dòng cuối \(AB\perp CB\) nha mình sửa ko đc:")

Xét \(\Delta OCD\) có \(\widehat{COD}+\widehat{OCD}+\widehat{ODC}=180^o\Rightarrow\widehat{OCD}+\widehat{ODC}=180^o-\widehat{COD}=180^o-110^o=70^o\)

CO, DO lần lượt là phân giác của \(\widehat{BCD},\widehat{ADC}\) nên \(\widehat{BCD}=2\widehat{OCD},\widehat{ADC}=2\widehat{ODC}\Rightarrow\widehat{BCD}+\widehat{ADC}=2\left(\widehat{OCD}+\widehat{ODC}\right)=2.70^o=140^o\)

Xét tứ giác ABCD có \(\widehat{A}+\widehat{B}+\widehat{C}+\widehat{D}=360^o\Rightarrow\widehat{A}+\widehat{B}=360^o-\left(\widehat{C}+\widehat{D}\right)=360^o-140^o=220^o\Rightarrow\widehat{A}=220^o-\widehat{B}\)

\(\widehat{A}-\widehat{B}=40^o\Rightarrow\left(220^o-\widehat{B}\right)-\widehat{B}=40^o\Rightarrow220^o-2\widehat{B}=40^o\Rightarrow2\widehat{B}=180^o\Rightarrow\widehat{B}=90^o\)

Do đó \(AB\perp CD\)

Hình như sai r á, thời gian đi từ A -> B là x, cả thgian đi và về là 5,5h thì thgian đi từ B -> A phải là 5,5 - x

Với sửa đk là x>0 vì thời gian ko thể là số âm đc nha