Tính \(\int\sin^2x\text{d}x\).
\(\dfrac{1}{2}x-\dfrac{1}{2}\sin2x+C\).\(\dfrac{1}{2}x-\dfrac{1}{4}\sin2x+C\).\(\cos^2x+C\).\(\dfrac{1}{2}\cos^2x+C\).Hướng dẫn giải:\(\int\sin^2x\text{d}x=\int\dfrac{1-\cos2x}{2}\text{d}x=\dfrac{1}{2}\int\text{d}x-\dfrac{1}{2}\int\cos2x\text{d}x\)
\(=\dfrac{1}{2}x-\dfrac{1}{4}\int\cos\left(2x\right)\text{d}\left(2x\right)=\dfrac{1}{2}x-\dfrac{1}{4}\sin2x+C\)