Tìm tập nghiệm của phương trình\(\left(\dfrac{3}{2}\right)^{2-2x}=\left(\dfrac{8}{27}\right)^{x-2}\).
\(\left\{\dfrac{8}{5}\right\}\).\(\left\{\dfrac{4}{5}\right\}\).\(\left\{8\right\}\).\(\left\{4\right\}\).Hướng dẫn giải: \(\left(\dfrac{3}{2}\right)^{2-2x}=\left(\dfrac{8}{27}\right)^{x-2}\) \(\Leftrightarrow\left(\dfrac{2}{3}\right)^{-\left(2-2x\right)}=\left(\dfrac{2}{3}\right)^{3\left(x-2\right)}\) \(\Leftrightarrow-\left(2-2x\right)=3\left(x-2\right)\) \(\Leftrightarrow x=4\)
