Tìm \(a\) biết \(\dfrac{4x^2y^2-y^2}{2x+1}=y^2\left(ax-1\right)\).
\(a=2.\)\(a=-2.\)\(a=1.\)\(a=-1.\)Hướng dẫn giải:Ta có \(\dfrac{4x^2y^2-y^2}{2x+1}=\dfrac{y^2\left(4x^2-1\right)}{2x+1}=\dfrac{y^2\left(2x-1\right)\left(2x+1\right)}{2x+1}=y^2\left(2x-1\right)\)
\(\Rightarrow a=2.\)
