Tích phân \(\int^{\dfrac{\pi}{2}}_0\left(2x-1-\sin x\right)\text{d}x\) bằng
\(\dfrac{\pi^2}{4}-\dfrac{\pi}{2}-1\).\(\dfrac{\pi^2}{4}-\dfrac{\pi}{2}+1\).\(\dfrac{\pi^2}{4}+\dfrac{\pi}{2}-1\).\(-\dfrac{\pi^2}{4}+\dfrac{\pi}{2}-1\).Hướng dẫn giải:\(\int^{\frac{\pi}{2}}_0\left(2x-1-\sin x\right)\text{d}x=\left(x^2-x+\cos x\right)|^{\frac{\pi}{2}}_0=\dfrac{\pi^2}{4}-\dfrac{\pi}{2}-1\).
