Sau khi thực hiện phép tính \(\dfrac{6x-18}{5x-10}.\dfrac{4-2x}{x+3}\), ta có kết quả là
\(\dfrac{-12\left(x-3\right)}{5\left(x+3\right)}\).\(\dfrac{12}{5}\).\(\dfrac{12\left(x+2\right)}{x-2}\).\(\dfrac{12\left(x-2\right)}{x+2}\).Hướng dẫn giải:\(\dfrac{6x-18}{5x-10}.\dfrac{4-2x}{x+3}\)
\(=\dfrac{6\left(x-3\right)}{5\left(x-2\right)}.\dfrac{2\left(2-x\right)}{x+3}\)
\(=\dfrac{-12\left(x-3\right)}{5\left(x+3\right)}\).